ECON 180 - Regulation and Antitrust Policy
Drake University, Spring 2015
William M. Boal

Course page: www.cbpa.drake.edu/econ/boal/180
Blackboard: bb.drake.edu
Email: william.boal@drake.edu

ANSWER KEY: COMPETITIVE FIRMS

Quiz 2 Version A

(1)d. (2)c. (3)a. (4)b. (5)a. (6)b. (7)b. (8)d. (9)b. (10)b.

Quiz 2 Version B

(1)b. (2)c. (3)b. (4)a. (5)c. (6)a. (7)d. (8)c. (9)c. (10)c.

Test 2 Version A

(1) [Profit maximization: 20 pts]

  1. MR = dRev/dq = 20 - (q/5).
  2. Firm does not take price as given because marginal revenue is not constant--it depends on the firm's own output level Q.
  3. MC = dTC/dq = 2 + (q/10).
  4. Set MR=MC and solve to get q*=60.

(2) [Profit maximization while taking price as given: 20 pts]

  1. Set MC(q) = P and solve to find q*. Here, MC(q) = 2 + (q/50) and P is given as $7, so q* = 250.
  2. Profit = Revenue - TC(q*) = P × q* - [2q* + (q*2/100)] = $625.

(3) [Short-run cost curves and supply: 20 pts]

  1. $4 = MC(600), since marginal cost is defined as the change in total cost caused by a one-unit change in output.
  2. $12 thousand = SATC × 1200, since SATC is defined as STC divided by output.
  3. $9 = minimum SATC.
  4. $5 = minimum SAVC.
  5. 1600 shovels (using rule P=MC).
  6. loss because price < breakeven price.
  7. 1800 shovels because price > breakeven price.
  8. profit because price > breakeven price.
  9. zero flashlights because price < shutdown price.
  10. loss equal to SFC.

(4) [Long-run cost and supply: 20 pts]

  1. MC(q) = dTC/dq = 3 q2 - 160 q + 1605.
  2. AC(q) = TC/q = q2 - 80 q + 1605.
  3. Breakeven price = minimum AC. So set derivative of AC equal to zero and solve to get qES=40.
  4. AC(qES) = $5 = breakeven price.
  5. Given the assumptions, long-run industry supply is a horizontal line at minimum AC = $5.

Critical thinking [10 pts]

Test 2 Version B

(1) [Profit maximization: 20 pts]

  1. MR = dRev/dq = 25 - (q/10).
  2. Firm does not take price as given because marginal revenue is not constant--it depends on the firm's own output level Q.
  3. MC = dTC/dq = 1 + (q/20).
  4. Set MR=MC and solve to get q*=160.

(2) [Profit maximization while taking price as given: 20 pts]

  1. Set MC(q) = P and solve to find q*. Here, MC(q) = 3 + (q/40) and P is given as $8, so q* = 200.
  2. Profit = Revenue - TC(q*) = P × q* - [3q* + (q*2/80)] = $500.

(3) [Short-run cost curves and supply: 20 pts]

  1. $12 = MC(1900), since marginal cost cost is defined as the change in total cost caused by a one-unit change in output.
  2. $25 thousand = SATC × 2500, since SATC is defined as STC divided by output.
  3. $2 = minimum SAVC.
  4. $7 = minimum SATC.
  5. 1300 shovels (using rule P=MC).
  6. loss because price < breakeven price.
  7. zero flashlights because price < shutdown price.
  8. loss equal to SFC.
  9. 1800 shovels because price > breakeven price.
  10. profit because price > breakeven price.

(4) [Long-run cost and supply: 20 pts]

  1. MC(q) = dTC/dq = 1.5 q2 - 120 q + 1806.
  2. AC(q) = TC/q = 0.5 q2 - 60 q + 1806.
  3. Breakeven price = minimum AC. So set derivative of AC equal to zero and solve to get qES=60.
  4. AC(qES) = $6 = breakeven price.
  5. Given the assumptions, long-run industry supply is a horizontal line at minimum AC = $6.

Critical thinking [10 pts]

[end of answer key]